4x^(2/3)-23x^(1/3)-6=0

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Solution for 4x^(2/3)-23x^(1/3)-6=0 equation: 


x in (-oo:+oo)

4*x^(2/3)-(23*x^(1/3))-6 = 0

4*x^(2/3)-23*x^(1/3)-6 = 0

t_1 = x^(1/3)

4*t_1^2-23*t_1^1-6 = 0

4*t_1^2-23*t_1-6 = 0

DELTA = (-23)^2-(-6*4*4)

DELTA = 625

DELTA > 0

t_1 = (625^(1/2)+23)/(2*4) or t_1 = (23-625^(1/2))/(2*4)

t_1 = 6 or t_1 = -1/4

t_1 = -1/4

x^(1/3)+1/4 = 0

1*x^(1/3) = -1/4 // : 1

x^(1/3) = -1/4

( -1/4 < 0 i 1/3 in (0:1) ) => x naleu017Cy do O

t_1 = 6

x^(1/3)-6 = 0

1*x^(1/3) = 6 // : 1

x^(1/3) = 6

x^(1/3) = 6 // ^ 3

x = 216

x = 216

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